| 1 | /* origin: OpenBSD /usr/src/lib/libm/src/ld80/e_expm1l.c */ |
| 2 | /* |
| 3 | * Copyright (c) 2008 Stephen L. Moshier <steve@moshier.net> |
| 4 | * |
| 5 | * Permission to use, copy, modify, and distribute this software for any |
| 6 | * purpose with or without fee is hereby granted, provided that the above |
| 7 | * copyright notice and this permission notice appear in all copies. |
| 8 | * |
| 9 | * THE SOFTWARE IS PROVIDED "AS IS" AND THE AUTHOR DISCLAIMS ALL WARRANTIES |
| 10 | * WITH REGARD TO THIS SOFTWARE INCLUDING ALL IMPLIED WARRANTIES OF |
| 11 | * MERCHANTABILITY AND FITNESS. IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR |
| 12 | * ANY SPECIAL, DIRECT, INDIRECT, OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES |
| 13 | * WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN AN |
| 14 | * ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING OUT OF |
| 15 | * OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS SOFTWARE. |
| 16 | */ |
| 17 | /* |
| 18 | * Exponential function, minus 1 |
| 19 | * Long double precision |
| 20 | * |
| 21 | * |
| 22 | * SYNOPSIS: |
| 23 | * |
| 24 | * long double x, y, expm1l(); |
| 25 | * |
| 26 | * y = expm1l( x ); |
| 27 | * |
| 28 | * |
| 29 | * DESCRIPTION: |
| 30 | * |
| 31 | * Returns e (2.71828...) raised to the x power, minus 1. |
| 32 | * |
| 33 | * Range reduction is accomplished by separating the argument |
| 34 | * into an integer k and fraction f such that |
| 35 | * |
| 36 | * x k f |
| 37 | * e = 2 e. |
| 38 | * |
| 39 | * An expansion x + .5 x^2 + x^3 R(x) approximates exp(f) - 1 |
| 40 | * in the basic range [-0.5 ln 2, 0.5 ln 2]. |
| 41 | * |
| 42 | * |
| 43 | * ACCURACY: |
| 44 | * |
| 45 | * Relative error: |
| 46 | * arithmetic domain # trials peak rms |
| 47 | * IEEE -45,+maxarg 200,000 1.2e-19 2.5e-20 |
| 48 | */ |
| 49 | |
| 50 | #include "libm.h" |
| 51 | |
| 52 | #if LDBL_MANT_DIG == 53 && LDBL_MAX_EXP == 1024 |
| 53 | long double expm1l(long double x) |
| 54 | { |
| 55 | 	return expm1(x); |
| 56 | } |
| 57 | #elif LDBL_MANT_DIG == 64 && LDBL_MAX_EXP == 16384 |
| 58 | |
| 59 | /* exp(x) - 1 = x + 0.5 x^2 + x^3 P(x)/Q(x) |
| 60 | -.5 ln 2 < x < .5 ln 2 |
| 61 | Theoretical peak relative error = 3.4e-22 */ |
| 62 | static const long double |
| 63 | P0 = -1.586135578666346600772998894928250240826E4L, |
| 64 | P1 = 2.642771505685952966904660652518429479531E3L, |
| 65 | P2 = -3.423199068835684263987132888286791620673E2L, |
| 66 | P3 = 1.800826371455042224581246202420972737840E1L, |
| 67 | P4 = -5.238523121205561042771939008061958820811E-1L, |
| 68 | Q0 = -9.516813471998079611319047060563358064497E4L, |
| 69 | Q1 = 3.964866271411091674556850458227710004570E4L, |
| 70 | Q2 = -7.207678383830091850230366618190187434796E3L, |
| 71 | Q3 = 7.206038318724600171970199625081491823079E2L, |
| 72 | Q4 = -4.002027679107076077238836622982900945173E1L, |
| 73 | /* Q5 = 1.000000000000000000000000000000000000000E0 */ |
| 74 | /* C1 + C2 = ln 2 */ |
| 75 | C1 = 6.93145751953125E-1L, |
| 76 | C2 = 1.428606820309417232121458176568075500134E-6L, |
| 77 | /* ln 2^-65 */ |
| 78 | minarg = -4.5054566736396445112120088E1L, |
| 79 | /* ln 2^16384 */ |
| 80 | maxarg = 1.1356523406294143949492E4L; |
| 81 | |
| 82 | long double expm1l(long double x) |
| 83 | { |
| 84 | 	long double px, qx, xx; |
| 85 | 	int k; |
| 86 | |
| 87 | 	if (isnan(x)) |
| 88 | 		return x; |
| 89 | 	if (x > maxarg) |
| 90 | 		return x*0x1p16383L; /* overflow, unless x==inf */ |
| 91 | 	if (x == 0.0) |
| 92 | 		return x; |
| 93 | 	if (x < minarg) |
| 94 | 		return -1.0; |
| 95 | |
| 96 | 	xx = C1 + C2; |
| 97 | 	/* Express x = ln 2 (k + remainder), remainder not exceeding 1/2. */ |
| 98 | 	px = floorl(0.5 + x / xx); |
| 99 | 	k = px; |
| 100 | 	/* remainder times ln 2 */ |
| 101 | 	x -= px * C1; |
| 102 | 	x -= px * C2; |
| 103 | |
| 104 | 	/* Approximate exp(remainder ln 2).*/ |
| 105 | 	px = (((( P4 * x + P3) * x + P2) * x + P1) * x + P0) * x; |
| 106 | 	qx = (((( x + Q4) * x + Q3) * x + Q2) * x + Q1) * x + Q0; |
| 107 | 	xx = x * x; |
| 108 | 	qx = x + (0.5 * xx + xx * px / qx); |
| 109 | |
| 110 | 	/* exp(x) = exp(k ln 2) exp(remainder ln 2) = 2^k exp(remainder ln 2). |
| 111 | 	 We have qx = exp(remainder ln 2) - 1, so |
| 112 | 	 exp(x) - 1 = 2^k (qx + 1) - 1 = 2^k qx + 2^k - 1. */ |
| 113 | 	px = scalbnl(1.0, k); |
| 114 | 	x = px * qx + (px - 1.0); |
| 115 | 	return x; |
| 116 | } |
| 117 | #elif LDBL_MANT_DIG == 113 && LDBL_MAX_EXP == 16384 |
| 118 | // TODO: broken implementation to make things compile |
| 119 | long double expm1l(long double x) |
| 120 | { |
| 121 | 	return expm1(x); |
| 122 | } |
| 123 | #endif |