| 1 | /* origin: FreeBSD /usr/src/lib/msun/src/e_jn.c */ |
| 2 | /* |
| 3 | * ==================================================== |
| 4 | * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved. |
| 5 | * |
| 6 | * Developed at SunSoft, a Sun Microsystems, Inc. business. |
| 7 | * Permission to use, copy, modify, and distribute this |
| 8 | * software is freely granted, provided that this notice |
| 9 | * is preserved. |
| 10 | * ==================================================== |
| 11 | */ |
| 12 | /* |
| 13 | * jn(n, x), yn(n, x) |
| 14 | * floating point Bessel's function of the 1st and 2nd kind |
| 15 | * of order n |
| 16 | * |
| 17 | * Special cases: |
| 18 | * y0(0)=y1(0)=yn(n,0) = -inf with division by zero signal; |
| 19 | * y0(-ve)=y1(-ve)=yn(n,-ve) are NaN with invalid signal. |
| 20 | * Note 2. About jn(n,x), yn(n,x) |
| 21 | * For n=0, j0(x) is called, |
| 22 | * for n=1, j1(x) is called, |
| 23 | * for n<=x, forward recursion is used starting |
| 24 | * from values of j0(x) and j1(x). |
| 25 | * for n>x, a continued fraction approximation to |
| 26 | * j(n,x)/j(n-1,x) is evaluated and then backward |
| 27 | * recursion is used starting from a supposed value |
| 28 | * for j(n,x). The resulting value of j(0,x) is |
| 29 | * compared with the actual value to correct the |
| 30 | * supposed value of j(n,x). |
| 31 | * |
| 32 | * yn(n,x) is similar in all respects, except |
| 33 | * that forward recursion is used for all |
| 34 | * values of n>1. |
| 35 | */ |
| 36 | |
| 37 | #include "libm.h" |
| 38 | |
| 39 | static const double invsqrtpi = 5.64189583547756279280e-01; /* 0x3FE20DD7, 0x50429B6D */ |
| 40 | |
| 41 | double jn(int n, double x) |
| 42 | { |
| 43 | 	uint32_t ix, lx; |
| 44 | 	int nm1, i, sign; |
| 45 | 	double a, b, temp; |
| 46 | |
| 47 | 	EXTRACT_WORDS(ix, lx, x); |
| 48 | 	sign = ix>>31; |
| 49 | 	ix &= 0x7fffffff; |
| 50 | |
| 51 | 	if ((ix | (lx|-lx)>>31) > 0x7ff00000) /* nan */ |
| 52 | 		return x; |
| 53 | |
| 54 | 	/* J(-n,x) = (-1)^n * J(n, x), J(n, -x) = (-1)^n * J(n, x) |
| 55 | 	 * Thus, J(-n,x) = J(n,-x) |
| 56 | 	 */ |
| 57 | 	/* nm1 = |n|-1 is used instead of |n| to handle n==INT_MIN */ |
| 58 | 	if (n == 0) |
| 59 | 		return j0(x); |
| 60 | 	if (n < 0) { |
| 61 | 		nm1 = -(n+1); |
| 62 | 		x = -x; |
| 63 | 		sign ^= 1; |
| 64 | 	} else |
| 65 | 		nm1 = n-1; |
| 66 | 	if (nm1 == 0) |
| 67 | 		return j1(x); |
| 68 | |
| 69 | 	sign &= n; /* even n: 0, odd n: signbit(x) */ |
| 70 | 	x = fabs(x); |
| 71 | 	if ((ix|lx) == 0 || ix == 0x7ff00000) /* if x is 0 or inf */ |
| 72 | 		b = 0.0; |
| 73 | 	else if (nm1 < x) { |
| 74 | 		/* Safe to use J(n+1,x)=2n/x *J(n,x)-J(n-1,x) */ |
| 75 | 		if (ix >= 0x52d00000) { /* x > 2**302 */ |
| 76 | 			/* (x >> n**2) |
| 77 | 			 * Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi) |
| 78 | 			 * Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi) |
| 79 | 			 * Let s=sin(x), c=cos(x), |
| 80 | 			 * xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then |
| 81 | 			 * |
| 82 | 			 * n sin(xn)*sqt2 cos(xn)*sqt2 |
| 83 | 			 * ---------------------------------- |
| 84 | 			 * 0 s-c c+s |
| 85 | 			 * 1 -s-c -c+s |
| 86 | 			 * 2 -s+c -c-s |
| 87 | 			 * 3 s+c c-s |
| 88 | 			 */ |
| 89 | 			switch(nm1&3) { |
| 90 | 			case 0: temp = -cos(x)+sin(x); break; |
| 91 | 			case 1: temp = -cos(x)-sin(x); break; |
| 92 | 			case 2: temp = cos(x)-sin(x); break; |
| 93 | 			default: |
| 94 | 			case 3: temp = cos(x)+sin(x); break; |
| 95 | 			} |
| 96 | 			b = invsqrtpi*temp/sqrt(x); |
| 97 | 		} else { |
| 98 | 			a = j0(x); |
| 99 | 			b = j1(x); |
| 100 | 			for (i=0; i<nm1; ) { |
| 101 | 				i++; |
| 102 | 				temp = b; |
| 103 | 				b = b*(2.0*i/x) - a; /* avoid underflow */ |
| 104 | 				a = temp; |
| 105 | 			} |
| 106 | 		} |
| 107 | 	} else { |
| 108 | 		if (ix < 0x3e100000) { /* x < 2**-29 */ |
| 109 | 			/* x is tiny, return the first Taylor expansion of J(n,x) |
| 110 | 			 * J(n,x) = 1/n!*(x/2)^n - ... |
| 111 | 			 */ |
| 112 | 			if (nm1 > 32) /* underflow */ |
| 113 | 				b = 0.0; |
| 114 | 			else { |
| 115 | 				temp = x*0.5; |
| 116 | 				b = temp; |
| 117 | 				a = 1.0; |
| 118 | 				for (i=2; i<=nm1+1; i++) { |
| 119 | 					a *= (double)i; /* a = n! */ |
| 120 | 					b *= temp; /* b = (x/2)^n */ |
| 121 | 				} |
| 122 | 				b = b/a; |
| 123 | 			} |
| 124 | 		} else { |
| 125 | 			/* use backward recurrence */ |
| 126 | 			/* x x^2 x^2 |
| 127 | 			 * J(n,x)/J(n-1,x) = ---- ------ ------ ..... |
| 128 | 			 * 2n - 2(n+1) - 2(n+2) |
| 129 | 			 * |
| 130 | 			 * 1 1 1 |
| 131 | 			 * (for large x) = ---- ------ ------ ..... |
| 132 | 			 * 2n 2(n+1) 2(n+2) |
| 133 | 			 * -- - ------ - ------ - |
| 134 | 			 * x x x |
| 135 | 			 * |
| 136 | 			 * Let w = 2n/x and h=2/x, then the above quotient |
| 137 | 			 * is equal to the continued fraction: |
| 138 | 			 * 1 |
| 139 | 			 * = ----------------------- |
| 140 | 			 * 1 |
| 141 | 			 * w - ----------------- |
| 142 | 			 * 1 |
| 143 | 			 * w+h - --------- |
| 144 | 			 * w+2h - ... |
| 145 | 			 * |
| 146 | 			 * To determine how many terms needed, let |
| 147 | 			 * Q(0) = w, Q(1) = w(w+h) - 1, |
| 148 | 			 * Q(k) = (w+k*h)*Q(k-1) - Q(k-2), |
| 149 | 			 * When Q(k) > 1e4 good for single |
| 150 | 			 * When Q(k) > 1e9 good for double |
| 151 | 			 * When Q(k) > 1e17 good for quadruple |
| 152 | 			 */ |
| 153 | 			/* determine k */ |
| 154 | 			double t,q0,q1,w,h,z,tmp,nf; |
| 155 | 			int k; |
| 156 | |
| 157 | 			nf = nm1 + 1.0; |
| 158 | 			w = 2*nf/x; |
| 159 | 			h = 2/x; |
| 160 | 			z = w+h; |
| 161 | 			q0 = w; |
| 162 | 			q1 = w*z - 1.0; |
| 163 | 			k = 1; |
| 164 | 			while (q1 < 1.0e9) { |
| 165 | 				k += 1; |
| 166 | 				z += h; |
| 167 | 				tmp = z*q1 - q0; |
| 168 | 				q0 = q1; |
| 169 | 				q1 = tmp; |
| 170 | 			} |
| 171 | 			for (t=0.0, i=k; i>=0; i--) |
| 172 | 				t = 1/(2*(i+nf)/x - t); |
| 173 | 			a = t; |
| 174 | 			b = 1.0; |
| 175 | 			/* estimate log((2/x)^n*n!) = n*log(2/x)+n*ln(n) |
| 176 | 			 * Hence, if n*(log(2n/x)) > ... |
| 177 | 			 * single 8.8722839355e+01 |
| 178 | 			 * double 7.09782712893383973096e+02 |
| 179 | 			 * long double 1.1356523406294143949491931077970765006170e+04 |
| 180 | 			 * then recurrent value may overflow and the result is |
| 181 | 			 * likely underflow to zero |
| 182 | 			 */ |
| 183 | 			tmp = nf*log(fabs(w)); |
| 184 | 			if (tmp < 7.09782712893383973096e+02) { |
| 185 | 				for (i=nm1; i>0; i--) { |
| 186 | 					temp = b; |
| 187 | 					b = b*(2.0*i)/x - a; |
| 188 | 					a = temp; |
| 189 | 				} |
| 190 | 			} else { |
| 191 | 				for (i=nm1; i>0; i--) { |
| 192 | 					temp = b; |
| 193 | 					b = b*(2.0*i)/x - a; |
| 194 | 					a = temp; |
| 195 | 					/* scale b to avoid spurious overflow */ |
| 196 | 					if (b > 0x1p500) { |
| 197 | 						a /= b; |
| 198 | 						t /= b; |
| 199 | 						b = 1.0; |
| 200 | 					} |
| 201 | 				} |
| 202 | 			} |
| 203 | 			z = j0(x); |
| 204 | 			w = j1(x); |
| 205 | 			if (fabs(z) >= fabs(w)) |
| 206 | 				b = t*z/b; |
| 207 | 			else |
| 208 | 				b = t*w/a; |
| 209 | 		} |
| 210 | 	} |
| 211 | 	return sign ? -b : b; |
| 212 | } |
| 213 | |
| 214 | |
| 215 | double yn(int n, double x) |
| 216 | { |
| 217 | 	uint32_t ix, lx, ib; |
| 218 | 	int nm1, sign, i; |
| 219 | 	double a, b, temp; |
| 220 | |
| 221 | 	EXTRACT_WORDS(ix, lx, x); |
| 222 | 	sign = ix>>31; |
| 223 | 	ix &= 0x7fffffff; |
| 224 | |
| 225 | 	if ((ix | (lx|-lx)>>31) > 0x7ff00000) /* nan */ |
| 226 | 		return x; |
| 227 | 	if (sign && (ix|lx)!=0) /* x < 0 */ |
| 228 | 		return 0/0.0; |
| 229 | 	if (ix == 0x7ff00000) |
| 230 | 		return 0.0; |
| 231 | |
| 232 | 	if (n == 0) |
| 233 | 		return y0(x); |
| 234 | 	if (n < 0) { |
| 235 | 		nm1 = -(n+1); |
| 236 | 		sign = n&1; |
| 237 | 	} else { |
| 238 | 		nm1 = n-1; |
| 239 | 		sign = 0; |
| 240 | 	} |
| 241 | 	if (nm1 == 0) |
| 242 | 		return sign ? -y1(x) : y1(x); |
| 243 | |
| 244 | 	if (ix >= 0x52d00000) { /* x > 2**302 */ |
| 245 | 		/* (x >> n**2) |
| 246 | 		 * Jn(x) = cos(x-(2n+1)*pi/4)*sqrt(2/x*pi) |
| 247 | 		 * Yn(x) = sin(x-(2n+1)*pi/4)*sqrt(2/x*pi) |
| 248 | 		 * Let s=sin(x), c=cos(x), |
| 249 | 		 * xn=x-(2n+1)*pi/4, sqt2 = sqrt(2),then |
| 250 | 		 * |
| 251 | 		 * n sin(xn)*sqt2 cos(xn)*sqt2 |
| 252 | 		 * ---------------------------------- |
| 253 | 		 * 0 s-c c+s |
| 254 | 		 * 1 -s-c -c+s |
| 255 | 		 * 2 -s+c -c-s |
| 256 | 		 * 3 s+c c-s |
| 257 | 		 */ |
| 258 | 		switch(nm1&3) { |
| 259 | 		case 0: temp = -sin(x)-cos(x); break; |
| 260 | 		case 1: temp = -sin(x)+cos(x); break; |
| 261 | 		case 2: temp = sin(x)+cos(x); break; |
| 262 | 		default: |
| 263 | 		case 3: temp = sin(x)-cos(x); break; |
| 264 | 		} |
| 265 | 		b = invsqrtpi*temp/sqrt(x); |
| 266 | 	} else { |
| 267 | 		a = y0(x); |
| 268 | 		b = y1(x); |
| 269 | 		/* quit if b is -inf */ |
| 270 | 		GET_HIGH_WORD(ib, b); |
| 271 | 		for (i=0; i<nm1 && ib!=0xfff00000; ){ |
| 272 | 			i++; |
| 273 | 			temp = b; |
| 274 | 			b = (2.0*i/x)*b - a; |
| 275 | 			GET_HIGH_WORD(ib, b); |
| 276 | 			a = temp; |
| 277 | 		} |
| 278 | 	} |
| 279 | 	return sign ? -b : b; |
| 280 | } |